Question

Following charged particles are projected perpendicular in a uniform magnetic field with the same velocity. The maximum force is exerted on:

• A. electron
• B. proton
• C. \( \alpha \)-particle
• D. deuteron

Hint:

The magnetic force on a charged particle is directly proportional to the charge of the particle. The electron, with the smallest charge, experiences the maximum force in a uniform magnetic field.

Answer 1

The Correct Option is A

The magnetic force on a moving charged particle is given by the equation:
\[ F = qvB \sin \theta \] Where:
- \( q \) is the charge of the particle,
- \( v \) is the velocity of the particle,
- \( B \) is the magnetic field strength,
- \( \theta \) is the angle between the velocity vector and the magnetic field.
Since the particles are projected perpendicular to the magnetic field, \( \sin \theta = 1 \). Thus, the force simplifies to:
\[ F = qvB \] The force depends on the charge \( q \) of the particle. The charge of an electron is the smallest among the given options, so the maximum force will be exerted on the electron.
Hence, the correct answer is option (A) electron.