Question

Fluorine molecule has bond order one. The number of electrons in the ant bonding molecular orbitals is two less than that in bonding molecular orbitals.

• A. If both Assertion and Reason are true and the Reason is the correct explanation of the Assertion
• B. If both Assertion and Reason are true but the reason is not the correct explanation of the Assertion
• C. If Assertion is true but Reason is false
• D. If both Assertion and Reason are false

Answer 1

The Correct Option is A

MO electronic configuration of $F _{2}$ molecule is $F _{2}=\sigma 1 s^{2}, \sigma^{*} 1 s^{2}, \sigma 2 s^{2}, \sigma^* 2 s^{2}, \sigma 2 p_{x}^{2}, $ $ \pi 2 p_{y}^{2} \approx \pi 2 p_{z}^{2}, \pi^{*} 2 p_{y}^{2} \approx \pi^* 2 p_{z}^{2} $ Bond order $=\frac{N_{b}-N_{a}}{2}$ where, $N_{b}=$ Number of electrons in bonding molecular orbitals $N_{a}=$ Number of electrons in antibonding molecular orbitals $=\frac{8-6}{2}=1$