Five friends A, B, C, D, and E bought cars which were priced differently.
The conditions are: - B's car was costlier than C's car but was less costly than E's car.
- A's car was costlier than D's car but less costly than C's car.
Whose car was the 2nd costliest?
Let's analyze the given conditions:
1. B's car is costlier than C's car but less costly than E's car: This means the order is E > B > C.
2. A's car is costlier than D's car but less costly than C's car: This means the order is A > D and A < C, so the order is A > D > C.
From these conditions, we can combine them to find the order of the cars: - E > B > C > A > D The second costliest car is B's car.
Thus, the correct answer is Option C.
If the roots of the quadratic equation \( ax^2 + bx + c = 0 \) are real and equal, then: