Five friends A, B, C, D, and E bought cars which were priced differently.
The conditions are: - B's car was costlier than C's car but was less costly than E's car.
- A's car was costlier than D's car but less costly than C's car.
Whose car was the 2nd costliest?
Let's analyze the given conditions:
1. B's car is costlier than C's car but less costly than E's car: This means the order is E > B > C.
2. A's car is costlier than D's car but less costly than C's car: This means the order is A > D and A < C, so the order is A > D > C.
From these conditions, we can combine them to find the order of the cars: - E > B > C > A > D The second costliest car is B's car.
Thus, the correct answer is Option C.

Statement: All flowers are beautiful. Some beautiful things are fragile.
Conclusion I: Some flowers are fragile.
Conclusion II: All beautiful things are flowers.
For the reaction \( A + B \to C \), the rate law is found to be \( \text{rate} = k[A]^2[B] \). If the concentration of \( A \) is doubled and \( B \) is halved, by what factor does the rate change?