Here, $m_{1}=1 \,kg , \overrightarrow{ v _{1}}=2 \hat{ i }$
$m_{2} =2 kg \overrightarrow{\vec{v}_{2}}=2 \cos 30 \hat{ i }-2 \sin 30 \hat{ j } $
$\vec{v}_{ cm } =\frac{m_{1} \overrightarrow{ v }_{1}+m_{2} \overrightarrow{ v _{2}}}{m_{1}+m_{2}} $
$=\frac{1 \times 2 \hat{i}+2(2 \cos 30 \hat{i}-2 \sin 30 \hat{i}}{1+2} $
$=\frac{2 \hat{i}+2 \sqrt{3} \hat{i}-2 \hat{j}}{3}$
$=\left(\frac{2+2 \sqrt{3}}{3}\right) \hat{i}-\frac{2}{3} \hat{j}$