(i) Diameter, d = 14 cm
Radius, r = \(\frac{14cm}{2}\) = 7cm
Surface area of a sphere = \(4\pi r^2\)
= 4 × \(\frac{22}{7}\) × 7cm × 7cm
= 616 cm2
(ii) Diameter, d = 21 cm
Radius, r = \(\frac{21cm}{2}\)
Surface area of a sphere = \(4\pi r^2\)
\(= \frac{4}{2} × \frac{22}{7} × \frac{21}{2} × \frac{21}{2}\)
= 1386 cm2
(iii) Diameter, d = 3.5 m
Radius, r =\( \frac{3.5}{2}\) = 1.75m
Surface area of a sphere = \(4\pi r^2\)
= 4 × \(\frac{22}{7} \)× 1.75m x 1.75m
= 38.5 m2
The surface area of a sphere with diameters 14 cm, 21 cm, and 3.5 m are 616 cm2, 1386 cm2, and 38.5 m2 respectively.
In Fig. 9.26, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠ BEC = 130° and ∠ ECD = 20°. Find ∠ BAC.