(i) Diameter, d = 14 cm
Radius, r = \(\frac{14cm}{2}\) = 7cm
Surface area of a sphere = \(4\pi r^2\)
= 4 × \(\frac{22}{7}\) × 7cm × 7cm
= 616 cm2
(ii) Diameter, d = 21 cm
Radius, r = \(\frac{21cm}{2}\)
Surface area of a sphere = \(4\pi r^2\)
\(= \frac{4}{2} × \frac{22}{7} × \frac{21}{2} × \frac{21}{2}\)
= 1386 cm2
(iii) Diameter, d = 3.5 m
Radius, r =\( \frac{3.5}{2}\) = 1.75m
Surface area of a sphere = \(4\pi r^2\)
= 4 × \(\frac{22}{7} \)× 1.75m x 1.75m
= 38.5 m2
The surface area of a sphere with diameters 14 cm, 21 cm, and 3.5 m are 616 cm2, 1386 cm2, and 38.5 m2 respectively.
When 3.0g of carbon is burnt in 8.00g oxygen, 11.00g of carbon dioxide is produced. What mass of carbon dioxide will be formed when 3.00g of carbon is burnt in 50.0g of oxygen? Which law of chemical combination will govern your answer?