(i) Diameter, d = 14 cm
Radius, r = \(\frac{14cm}{2}\) = 7cm
Surface area of a sphere = \(4\pi r^2\)
= 4 × \(\frac{22}{7}\) × 7cm × 7cm
= 616 cm2
(ii) Diameter, d = 21 cm
Radius, r = \(\frac{21cm}{2}\)
Surface area of a sphere = \(4\pi r^2\)
\(= \frac{4}{2} × \frac{22}{7} × \frac{21}{2} × \frac{21}{2}\)
= 1386 cm2
(iii) Diameter, d = 3.5 m
Radius, r =\( \frac{3.5}{2}\) = 1.75m
Surface area of a sphere = \(4\pi r^2\)
= 4 × \(\frac{22}{7} \)× 1.75m x 1.75m
= 38.5 m2
The surface area of a sphere with diameters 14 cm, 21 cm, and 3.5 m are 616 cm2, 1386 cm2, and 38.5 m2 respectively.
(Street Plan) : A city has two main roads which cross each other at the centre of the city. These two roads are along the North-South direction and East-West direction.
All the other streets of the city run parallel to these roads and are 200 m apart. There are 5 streets in each direction. Using 1cm = 200 m, draw a model of the city on your notebook. Represent the roads/streets by single lines. There are many cross- streets in your model. A particular cross-street is made by two streets, one running in the North - South direction and another in the East - West direction. Each cross street is referred to in the following manner : If the 2nd street running in the North - South direction and 5th in the East - West direction meet at some crossing, then we will call this cross-street (2, 5). Using this convention, find:
(i) how many cross - streets can be referred to as (4, 3).
(ii) how many cross - streets can be referred to as (3, 4).