L.C.M. of 18, 24 and 32 = 2 x 2 x 2 x 2 x 2 x 3 x 3 = 288
The smallest four-digit number = 1000
Therefore, the required number is 1000 + (288 – 136) = 1152.
Complete the drawing shown in Fig. 9.14 to indicate where the free ends of the two wires should be joined to make the bulb glow