We need to simplify the Boolean expression \( Y = A'BC' + AC' \)
We can factor out the common term C':
$$ Y = C'(A'B + A) $$
Now we use the Boolean algebra identity \( X + X'Y = X + Y \)
In our case, let \(X=A\) and \(Y=B\)
The term inside the parenthesis is \(A + A'B\)
Applying the identity, we get:
$$ A + A'B = A + B $$
Substituting this back into the expression for Y:
$$ Y = C'(A + B) $$
This is equivalent to \( (A+B)C' \)