Find the remainder when the $41$-digit number $1234\ldots$ is divided by $8$.
$4$
Interpreting $1234\ldots$ as the string $1234567891011\ldots$ continued until $41$ digits. Only the \emph{last three} digits matter mod $8$. Digits $1$–$9$ use $9$ places; remaining $32$ places are from two-digit numbers. That is $16$ numbers: $10$ to $25$. The final three digits are the last digit of $24$ and both digits of $25$, i.e. $425$. \[ 425 \div 8=53 \text{ remainder } 1. \] So the remainder is $1$.
Find the missing code:
L1#1O2~2, J2#2Q3~3, _______, F4#4U5~5, D5#5W6~6