Find the ratio in which the line segment joining the points (– 3, 10) and (6, – 8) is divided by (– 1, 6).
Let the ratio in which the line segment joining (−3, 10) and (6, −8) is divided by point (−1, 6) be k:1.
Therefore, \(-1=\frac{6k-3}{k+1}\)
-k-1=6k-3
7k=2
k=\(\frac{2}{7}\)
Therefore,the required ratio is 2:7
Given $\triangle ABC \sim \triangle PQR$, $\angle A = 30^\circ$ and $\angle Q = 90^\circ$. The value of $(\angle R + \angle B)$ is

परंपरागत भोजन को लोकप्रिय कैसे बनाया जा सकता है ?
i. उपलब्ध करवाकर
ii. प्रचार-प्रसार द्वारा
iii. बिक्री की विशेष व्यवस्था करके
iv. घर-घर मुफ्त अभियान चलाकर विकल्प: