Question

Find the.

1. Probability of the pointer stopping on D in (Question 1-(a))?
2. Probability of getting an ace from a well shuffled deck of \(52\) playing cards?
3. Probability of getting a red apple. (See figure below)

Answer 1

(a) In a spinning wheel, there are five pointers \(A, A, B, C, D\). 
So there are five outcomes. 
Pointer stops at \(D\) which is one outcome. 
So the probability of the pointer stopping on \(D = \frac{1}{5}\)

---

(b) There are \(4\) aces in a deck of \(52\) playing cards. 
So, there are four events of getting an ace. 
So, probability of getting an ace = \(\frac{4}{42}\)=\(\frac{1}{4}\) 

---

(c) Total number of apples = \(7\) 
Number of red apples = \(4\) 
Probability of getting red apple = \(\frac{4}{7}\)