Question

Find the probability of getting at most 2 heads when 4 coins are tossed.

• A. \( \frac{5}{16} \)
• B. \( \frac{3}{8} \)
• C. \( \frac{7}{16} \)
• D. \( \frac{1}{2} \)

Hint:

Use the binomial coefficient to calculate the number of outcomes for each possible number of heads when tossing multiple coins.

Answer 1

The Correct Option is C

When 4 coins are tossed, the total number of possible outcomes is \( 2^4 = 16 \). The number of outcomes with 0, 1, or 2 heads can be found using the binomial distribution: - Number of outcomes with 0 heads: \( \binom{4}{0} = 1 \) - Number of outcomes with 1 head: \( \binom{4}{1} = 4 \) - Number of outcomes with 2 heads: \( \binom{4}{2} = 6 \) Thus, the total number of outcomes with at most 2 heads is \( 1 + 4 + 6 = 11 \). The probability is: \[ P(\text{at most 2 heads}) = \frac{11}{16} \]