Question:

Find the odd one out: 396, 462, 572, 427, 671, 264

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Look for patterns in the sum of digits of numbers to identify the odd one out.
Updated On: Mar 25, 2025
  • 396
  • 671
  • 427
  • 264
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The Correct Option is C

Solution and Explanation

We need to identify the number that does not follow the pattern in the given series: \[ 396, 462, 572, 427, 671, 264. \] Step 1: Compute the sum of the digits for each number \[ 396: 3 + 9 + 6 = 18 \] \[ 462: 4 + 6 + 2 = 12 \] \[ 572: 5 + 7 + 2 = 14 \] \[ 427: 4 + 2 + 7 = 13 \] \[ 671: 6 + 7 + 1 = 14 \] \[ 264: 2 + 6 + 4 = 12 \] Step 2: Identify the odd one out Observing the sums of the digits: - \( 18, 12, 14, 14, 12 \) are all even numbers. - \( 13 \) (from 427) is the only odd number. Since all numbers except \( 427 \) have even sums, the number that does not follow the pattern is: \[ \boxed{427} \]
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