Numbers are 1, 2, ..., 15, with equal probability \( \frac{1}{15} \). Mean (expected value):
\[
E(X) = \sum_{i=1}^{15} i \cdot \frac{1}{15} = \frac{1}{15} \cdot \frac{15 \cdot 16}{2} = \frac{120}{15} = 8.
\]
Alternatively, for a uniform distribution over \( \{1, 2, ..., n\} \), mean = \( \frac{n + 1}{2} = \frac{15 + 1}{2} = 8 \).
Answer: 8.