We need to maximize \( z = x + y \), subject to the constraints:
\[
x - y \leq -1, -x + y \leq 0, x \geq 0, y \geq 0.
\]
We begin by graphing the constraints:
1. \( x - y \leq -1 \) represents a line with slope 1 and intercept -1.
2. \( -x + y \leq 0 \) represents a line with slope 1 and intercept 0.
3. \( x \geq 0 \) is the region to the right of the y-axis.
4. \( y \geq 0 \) is the region above the x-axis.
The feasible region is the area bounded by these lines. We can find the vertices of this region by solving the system of equations:
1. Solve \( x - y = -1 \) and \( -x + y = 0 \):
\[
x - y = -1 \text{(i)}
\]
\[
-x + y = 0 \text{(ii)}
\]
From (ii), \( x = y \). Substituting into (i):
\[
x - x = -1 $\Rightarrow$ 0 = -1,
\]
which is a contradiction, meaning there is no solution.
Next, solve for other pairs of constraints to determine the vertices.