Find the general solution of the differential equation: cosx (1 + cosy) dx - siny (1 + sinx) dy = 0
Step 1: Rearrange the equation:
We start with the given equation:
\[
\cos(x)(1 + \cos(y)) \, dx = \sin(y)(1 + \sin(x)) \, dy
\]
Step 2: Divide both sides by \( \cos(x)(1 + \cos(y)) \):
Rearranging the equation to isolate \( \frac{dx}{dy} \):
\[
\frac{dx}{dy} = \frac{\sin(y)(1 + \sin(x))}{\cos(x)(1 + \cos(y))}
\]
Step 3: Simplify using trigonometric identities:
To simplify further, we can use the Pythagorean identity \( \sin^2(x) + \cos^2(x) = 1 \). We introduce the identity into the equation to make the terms easier to handle:
\[
\frac{dx}{dy} = \frac{\sin(y)(1 + \sin(x))}{\cos(x)(1 + \cos(y))} \times \frac{\sin^2(x) + \cos^2(x)}{\sin^2(x) + \cos^2(x)}
\]
This results in:
\[
\frac{dx}{dy} = \frac{\sin(y)(1 + \sin(x)) \sin^2(x)}{\cos(x)(1 + \cos(y))(\sin^2(x) + \cos^2(x))}
\]
Step 4: Further simplification:
After simplifying, we have:
\[
\frac{dx}{dy} = \frac{\sin(y) \sin(x) (1 + \sin(x))}{\cos(x)(1 + \cos(y))}
\]
Step 5: Separate the variables:
Now, we separate the variables to isolate \( dx \) and \( dy \). Multiply both sides by \( dy \):
\[
dy = \frac{\cos(x)(1 + \cos(y))}{\sin(y) \sin(x)(1 + \sin(x))} \, dx
\]
This simplifies to:
\[
dy = \frac{\cos(x)}{\sin(x)} \cdot \frac{1 + \cos(y)}{\sin(y)(1 + \sin(x))} \, dx
\]
Step 6: Set up the integral:
We can now integrate both sides of the equation. The left-hand side integrates to \( y \), and the right-hand side involves a more complicated integral:
\[
\int dy = \int \frac{\cos(x)}{\sin(x)} \cdot \frac{1 + \cos(y)}{\sin(y)(1 + \sin(x))} \, dx
\]
Thus, the general solution is:
\[
y = \int \frac{\cos(x)}{\sin(x)} \cdot \frac{1 + \cos(y)}{\sin(y)(1 + \sin(x))} \, dx + C
\]
where \( C \) is the constant of integration.
Final Answer:
Unfortunately, the integral on the right-hand side does not have a simple closed-form solution. Therefore, the general solution of the given differential equation is:
\[
y = \int \frac{\cos(x)}{\sin(x)} \cdot \frac{1 + \cos(y)}{\sin(y)(1 + \sin(x))} \, dx + C
\]
where \( C \) is the constant of integration.
Let \( f : \mathbb{R} \to \mathbb{R} \) be a twice differentiable function such that \( f(x + y) = f(x) f(y) \) for all \( x, y \in \mathbb{R} \). If \( f'(0) = 4a \) and \( f \) satisfies \( f''(x) - 3a f'(x) - f(x) = 0 \), where \( a > 0 \), then the area of the region R = {(x, y) | 0 \(\leq\) y \(\leq\) f(ax), 0 \(\leq\) x \(\leq\) 2 is :
A relation between involved variables, which satisfy the given differential equation is called its solution. The solution which contains as many arbitrary constants as the order of the differential equation is called the general solution and the solution free from arbitrary constants is called particular solution.
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