Let the coordinates of P be (x, y, z). The coordinates of points A and B are (4, 0, 0) and (- 4, 0, 0) respectively. It is given that PA + PB = 10. ⇒\(\sqrt{(x-4)^2+y^2+z^2}+\sqrt{(x+4)^2+y^2+z^2}\) = 10 ⇒\(\sqrt{(x-4)^2+y^2+z^2}\) = 10 − \(\sqrt{(x+4)^2+y^2+z^2}\) On squaring both sides, we obtain ⇒ \({(x-4)^2+y^2+z^2}\) = \(100-20\sqrt{(x+4)^2+y^2+z^2+(x+4)^2+y^2+z^2}\) ⇒\(x^2-8x+16+y^2+z^2\) = \(100-20\sqrt{x^2+8x+16+y^2+z^2+x^2+8x+16+y^2+z^2}\) ⇒ 5\(\sqrt{x^2+8x+16+y^2+z^2}\) = (25+4x) On squaring both sides again, we obtain 25 (\(\sqrt{x^2+8x+16+y^2+z^2}\)) = 625 +16x2 + 200x ⇒ 9x2 + 25y2 + 25z2 - 225 = 0 Thus, the required equation is 9x2+ 25y2+25z - 225 = 0.