The equation of the plane ZOX is y=0
Any plane parallel to it is of the form, y=a
Since, the y-intercept of the plane is 3,
∴ a=3
Thus, the equation of the required plane is y=3.
Show that the following lines intersect. Also, find their point of intersection:
Line 1: \[ \frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4} \]
Line 2: \[ \frac{x - 4}{5} = \frac{y - 1}{2} = z \]
Information Table
| Information | Amount (₹) |
|---|---|
| Preference Share Capital | 8,00,000 |
| Equity Share Capital | 12,00,000 |
| General Reserve | 2,00,000 |
| Balance in Statement of Profit and Loss | 6,00,000 |
| 15% Debentures | 4,00,000 |
| 12% Loan | 4,00,000 |
| Revenue from Operations | 72,00,000 |
A surface comprising all the straight lines that join any two points lying on it is called a plane in geometry. A plane is defined through any of the following uniquely: