To differentiate \( \log(\cos x) \), we use the chain rule. The derivative of \( \log(u) \) is \( \frac{1}{u} \), and then we differentiate \( \cos x \) to get \( -\sin x \). Thus:
\[
\frac{d}{dx} \left( \log(\cos x) \right) = \frac{1}{\cos x} \cdot (-\sin x) = -\frac{\sin x}{\cos x}
\]
This simplifies to:
\[
-\tan x
\]
Therefore, the correct option is:
\[
\boxed{-\tan x}
\]