Question:

Find ratio of angular speeds of second hand and minute hand?

Updated On: Apr 13, 2025
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Solution and Explanation

The second hand of a clock completes one full rotation in 60 seconds, while the minute hand completes one full rotation in 60 minutes, or 3600 seconds. To find the ratio of the angular speeds of the second hand and the minute hand, we use the following formula:

\[ \frac{\text{Angular speed of second hand}}{\text{Angular speed of minute hand}} = \frac{2\pi \text{ radians}}{60 \text{ seconds}} \div \frac{2\pi \text{ radians}}{3600 \text{ seconds}} \]

Now, simplifying this expression step-by-step:

\[ \frac{\text{Angular speed of second hand}}{\text{Angular speed of minute hand}} = \frac{\frac{2\pi}{60}}{\frac{2\pi}{3600}} \]

Multiplying by the reciprocal of the second term:

\[ \frac{\text{Angular speed of second hand}}{\text{Angular speed of minute hand}} = \frac{2\pi}{60} \times \frac{3600}{2\pi} \]

Notice that the factors of \(2\pi\) cancel each other out:

\[ \frac{\text{Angular speed of second hand}}{\text{Angular speed of minute hand}} = \frac{3600}{60} = 60 \]

Therefore, the ratio of the angular speeds of the second hand and minute hand is 60:1. This means that the second hand rotates 60 times faster than the minute hand.

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Concepts Used:

Trigonometric Equations

Trigonometric equation is an equation involving one or more trigonometric ratios of unknown angles. It is expressed as ratios of sine(sin), cosine(cos), tangent(tan), cotangent(cot), secant(sec), cosecant(cosec) angles. For example, cos2 x + 5 sin x = 0 is a trigonometric equation. All possible values which satisfy the given trigonometric equation are called solutions of the given trigonometric equation.

A list of trigonometric equations and their solutions are given below: 

Trigonometrical equationsGeneral Solutions
sin θ = 0θ = nπ
cos θ = 0θ = (nπ + π/2)
cos θ = 0θ = nπ
sin θ = 1θ = (2nπ + π/2) = (4n+1) π/2
cos θ = 1θ = 2nπ
sin θ = sin αθ = nπ + (-1)n α, where α ∈ [-π/2, π/2]
cos θ = cos αθ = 2nπ ± α, where α ∈ (0, π]
tan θ = tan αθ = nπ + α, where α ∈ (-π/2, π/2]
sin 2θ = sin 2αθ = nπ ± α
cos 2θ = cos 2αθ = nπ ± α
tan 2θ = tan 2αθ = nπ ± α