Question

Find: (i) 9 \(\frac{3}{2}\) (ii) 32 \(\frac{2}{5}\) (iii) 16 \(\frac{3}{4}\) (iv) 125 -\(\frac{1}{3}\)

Answer 1

(i) 9 \(\frac{3}{2}\) = (9 \(\frac{1}{2}\))3 \(\frac{1}{3}\)= (3)³ = 27

(ii) 32 \(\frac{2}{5}\) = (32 \(\frac{1}{5}\))2 = (2)² = 4

(iii) 16 \(\frac{3}{4}\) = (16\(\frac{1}{4}\))3 = (2)³ = 8

(iv) 125 -\(\frac{1}{3}\) = \(\frac{1}{(125)}\frac{1}{3}\) = \(\frac{1}{5}\)