This is a circuit analysis problem where we use Kirchhoff’s current law (KCL) and Ohm’s law to calculate the currents. The currents \( I_1 \), \( I_2 \), and \( I_3 \) can be found by solving the simultaneous equations formed by applying KCL at the junctions and Ohm’s law for each resistor.
By applying KCL and solving for the currents, we find that \( I_1 = -2A \), \( I_2 = 1A \), and \( I_3 = 1A \).
Final Answer:
\[
\boxed{-2A, 1A, 1A}
\]