We are asked to differentiate \( \log 5x \) with respect to \( x \).
Using the chain rule:
\[
\frac{d}{dx} \left( \log 5x \right) = \frac{d}{dx} \left( \log 5 + \log x \right)
\]
Since \( \log 5 \) is a constant, its derivative is zero. Thus:
\[
\frac{d}{dx} \left( \log 5x \right) = \frac{d}{dx} \left( \log x \right) = \frac{1}{x}
\]
But because we have \( 5x \) and not just \( x \), we must apply the chain rule:
\[
\frac{d}{dx} \left( \log 5x \right) = \frac{1}{5x} \times \frac{d}{dx} (5x) = \frac{1}{5x} \times 5 = \frac{1}{x}
\]
Thus, the correct answer is \( \frac{1}{5x} \).