Question:

Find \( \frac{d}{dx} \left( \log 5x \right) \).

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When differentiating logarithmic functions, use the chain rule to account for any coefficients inside the logarithm.
  • \( \frac{1}{5x} \)
  • \( \frac{1}{x} \)
  • \( \frac{5}{x} \)
  • \( \log 5 + \frac{1}{x} \)
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The Correct Option is A

Solution and Explanation

We are asked to differentiate \( \log 5x \) with respect to \( x \). Using the chain rule: \[ \frac{d}{dx} \left( \log 5x \right) = \frac{d}{dx} \left( \log 5 + \log x \right) \] Since \( \log 5 \) is a constant, its derivative is zero. Thus: \[ \frac{d}{dx} \left( \log 5x \right) = \frac{d}{dx} \left( \log x \right) = \frac{1}{x} \] But because we have \( 5x \) and not just \( x \), we must apply the chain rule: \[ \frac{d}{dx} \left( \log 5x \right) = \frac{1}{5x} \times \frac{d}{dx} (5x) = \frac{1}{5x} \times 5 = \frac{1}{x} \] Thus, the correct answer is \( \frac{1}{5x} \).
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