Let the time taken by pipe B alone be \( x \) minutes.
Since pipe A is 3 times faster, it takes:
\[
\frac{x}{3} \text{ minutes}
\]
Given that A takes 32 minutes less:
\[
\frac{x}{3} = x - 32
\]
Solving for \( x \):
\[
x - \frac{x}{3} = 32
\]
\[
\frac{2x}{3} = 32
\]
\[
2x = 96
\]
\[
x = 48
\]
Thus, pipe B alone takes 48 minutes, and pipe A alone takes:
\[
\frac{48}{3} = 16 \text{ minutes}
\]
Their rates of filling are:
\[
\frac{1}{48}, \quad \frac{1}{16}
\]
Total rate when both work together:
\[
\frac{1}{48} + \frac{1}{16} = \frac{4}{48} = \frac{1}{12}
\]
Time to fill:
\[
12 \text{ minutes}
\]