Figure shows two parallel plates (upper plate at \( x = b \) and lower one at \( x = -b \) of length L (aligned in \( z \)-direction and infinite width (in \( y \)-direction, normal to the plane of the figure)). Two immiscible, incompressible liquids are flowing steadily in the \( z \)-direction through the thin passage between the plates under the influence of a horizontal pressure gradient \( \left( \frac{P_0 - P_L}{L} \right) \). During the flow, the passage is always half-filled with denser fluid I (viscosity \( \mu_1 \)) at the bottom and rest is occupied by lighter fluid II (viscosity \( \mu_2 \)). Considering exactly in between the fluids and no instabilities in the flow, the shear stress \( \tau_{xz} \) is expressed as:
\[ \tau_{xz} = \frac{(P_0 - P_L) b}{L} \left( \frac{x}{b} - \frac{1}{2} \right) \left( \frac{\mu_1' - \mu_2'}{\mu_1' + \mu_2'} \right) \] Which one of the following options correctly identifies the location of the point having maximum velocity of the flow?
Suppose that 2 is an eigenvalue of the matrix
Then the value of \( \alpha \) is equal to (Answer in integer):
In the figures given below, L and H indicate low and high pressure centers, respectively; PGF, CoF and CeF indicate Pressure Gradient Force, Coriolis Force and Centrifugal Force, respectively; \( V \) is Velocity. [The arrows indicate only the directions but not the magnitudes of the forces and velocity.]
Which of the following is/are the correct representation(s) of the directions of various forces and velocity in the gradient wind balance in the northern hemisphere?
Which of the following is the correct form of the mass divergence form of the continuity equation for a compressible fluid? [In the given equations, \( \rho \) is the density and \( \nabla \) the three-dimensional velocity vector of the fluid.]
[(i)] $\displaystyle \frac{\partial \rho}{\partial t} + \nabla \times (\rho \mathbf{v}) = 0$
[(ii)] $\displaystyle \frac{\partial \rho}{\partial t} + \nabla \cdot (\rho \mathbf{v}) = 0$
[(iii)] $\displaystyle \frac{\partial \mathbf{v}}{\partial t} + \rho \cdot \nabla \mathbf{v} = 0$
[(iv)] $\displaystyle \frac{\partial \rho}{\partial t} + \mathbf{v} \cdot \nabla \rho = 0$