(a) ∵ 1 g = \(\frac {1}{1000}\) kg
∴ 2 g = \(\frac {1}{1000} \times 2\) = 0.002 kg
(b) ∵ 1 g = \(\frac {1}{1000}\) kg
∴ 100 g = \(\frac {1}{1000} \times 100 \) = 0.1 kg
(c) ∵ 1 g = \(\frac {1}{1000}\) kg
∴ 3750 g = \(\frac {1}{1000} \times 3750\) = 3.750 kg
(d) ∵ 1 g = \(\frac {1}{1000}\) kg
∴ 5 kg 8 g = 5 + \(\frac {1}{1000} \times 8\) = 5.008 kg
(e) ∵ 1 g = \(\frac {1}{1000}\) kg
∴ 26 kg 50 g = 26 + \(\frac {1}{1000} \times 50\) = 26.050 kg
Complete the drawing shown in Fig. 9.14 to indicate where the free ends of the two wires should be joined to make the bulb glow