Step 1: Understanding the Concept:
This is a Data Sufficiency problem involving time, speed, and distance. The question is a "Yes/No" question. To be sufficient, the information must lead to a definite "Yes" or a definite "No" answer. The question asks if the total journey time was less than or equal to 40 minutes (from 10:00 AM to 10:40 AM).
Step 2: Key Formula or Approach:
Let \(D\) be the distance from the house to the park.
Let \(T_1\) and \(S_1\) be the time taken and average speed while going to the park.
Let \(T_2\) and \(S_2\) be the time taken and average speed while returning home.
Total time for the journey = \(T_1 + T_2\).
The question is: Is \(T_1 + T_2 \le 40\) minutes?
Step 3: Detailed Explanation:
Analyze Statement (1): Abhay's average speed while riding back home was 10% slower than his average speed while riding to the park.
This means \(S_2 = S_1 \times (1 - 0.10) = 0.9 \times S_1\).
Since the distance is the same for both legs of the journey (\(D\)), and \(T = D/S\), we can establish a relationship between the times:
\[ T_2 = \frac{D}{S_2} = \frac{D}{0.9 \times S_1} = \frac{1}{0.9} \times \frac{D}{S_1} = \frac{10}{9} \times T_1 \]
The total time is \(T_1 + T_2 = T_1 + \frac{10}{9}T_1 = \frac{19}{9}T_1\).
The question becomes: Is \(\frac{19}{9}T_1 \le 40\)?
We do not know the value of \(T_1\). If \(T_1 = 18\) minutes, total time is \(\frac{19}{9} \times 18 = 38\) minutes (Yes). If \(T_1 = 20\) minutes, total time is \(\frac{19}{9} \times 20 \approx 42.2\) minutes (No).
Statement (1) alone is not sufficient.
Analyze Statement (2): Abhay arrived at the park at 10:18 AM.
Since he started at 10:00 AM, the time to get to the park, \(T_1\), is 18 minutes.
The total time is \(18 + T_2\). The question is: Is \(18 + T_2 \le 40\), or is \(T_2 \le 22\)?
We have no information about his speed on the return trip, so we don't know \(T_2\). It could be less than or greater than 22 minutes.
Statement (2) alone is not sufficient.
Analyze Both Statements Together:
From Statement (2), we know \(T_1 = 18\) minutes.
From Statement (1), we know the relationship \(T_2 = \frac{10}{9}T_1\).
We can now calculate the exact value of \(T_2\):
\[ T_2 = \frac{10}{9} \times 18 = 10 \times 2 = 20 \text{ minutes} \]
The total journey time is \(T_1 + T_2 = 18 + 20 = 38\) minutes.
Is the total time of 38 minutes less than or equal to 40 minutes? Yes.
Since we have a definite "Yes" answer, the statements together are sufficient.