Question:

Evaluate \([i^{18}+(\frac{1}{i})^{25}]^3.\)

Updated On: Oct 23, 2023
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Solution and Explanation

\([i^{18}+(\frac{1}{i})^{25}]^3\)

=\([i^{4×4+2}+(\frac{1}{i^{4×4+1}})]^3\)

=\([i^{(4)^4.i^2}+\frac{1}{(i^{4})^6.i}]^3\)

\(=[i^2+\frac{1}{i}]^3\)        \([i^{-4}=1]\)

\(=[-1+\frac{1}{i}×\frac{1}{i}]^3\)                \([i^4=-1]\)

\(=[-1+\frac{i}{i^2}]^3\)

\(=[-1-i]^3\)

=\((-1)^3[1+i]^3\)

\(=[1^3+i^3+3.1.i(1+i)]\)

\(=-[1+i^3+3i+3i^2]\)

\(=-[1+i^3+3i+3i^2]\)

\(=-[1-i+3i-3]\)

\(=-[-2+2i]\)

\(=2-2i\)

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Concepts Used:

Complex Number

A Complex Number is written in the form

a + ib

where,

  • “a” is a real number
  • “b” is an imaginary number

The Complex Number consists of a symbol “i” which satisfies the condition i^2 = −1. Complex Numbers are mentioned as the extension of one-dimensional number lines. In a complex plane, a Complex Number indicated as a + bi is usually represented in the form of the point (a, b). We have to pay attention that a Complex Number with absolutely no real part, such as – i, -5i, etc, is called purely imaginary. Also, a Complex Number with perfectly no imaginary part is known as a real number.