Question:

Ethyl bromide is industrially prepared from

Updated On: Jul 28, 2022
  • ethyl alcohol $+ HBr$
  • ethanol $+ Br_2$
  • alcohol $+ HBr$
  • none of these
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The Correct Option is A

Solution and Explanation

Industrial preparation o f ethyl bromide - By refluxing the alcohol with constant boiling HBr $(48 \%)$ in presence o f little concentrated sulphuric acid $C_{2}H_{5}OH+HBr$ $ { ->[{H_{2}SO_{4} {\text(conc.)}}][{\text{reflux}}] } C_{2}H_{5}Br+H_{2}O$
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Concepts Used:

Preparation of Haloalkanes

  1. Preparation by Alcohols: By using alcohol, we can very easily prepare Haloalkane as when R-OH is reacted with a suitable reagent it will form R-X. The following reagents will help in the formation of the reactions:
    1. Halogen Acids (HX)
    2. Thionyl chloride (SOCl2)
    3. Phosphorous halides (PX5 or PX3)
  2. Preparation by Free Radical Halogenation: The formation of alkyl bromides and alkyl chloride is very much possible with the help of free radical halogenation, but as these radicals are highly reactive and non-specific in nature, they can result in the formation of a mixture of products. Though, it's not a preferred method for the preparation of haloalkanes. For example, free radical chlorination can result in the formation of a number of haloalkanes, which in turn makes it difficult to set apart a single product.
  3. Preparation by Alkenes: An electrophilic addition reaction can be used to transform an alkene into a haloalkane as alkene will react with HX to form R-X.

Read More: Haloalkanes and Haloarenes