Question:

Empirical formula of a compound is $CH_2O$ and its molecular mass is $90$, the molecular formula of the compound is

Updated On: Jul 12, 2022
  • $C_3H_6O_3$
  • $C_2H_4O_2$
  • $C_6H_{12}O_6$
  • $CH_2O$
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The Correct Option is A

Solution and Explanation

The empirical formula of compound $= CH _{2} O$ Empirical formula mass $=(1 \times 12)+(2 \times 1)+(1 \times 16)=30$ Molecular mass $=90$ $\therefore n=\frac{\text { Molecular mass }}{\text { Empirical mass }}=\frac{90}{30}=3$ and molecular formula $=3 \times CH _{2} O$ $= C _{3} H _{6} O _{3}$
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Top Questions on Organic Chemistry- Some Basic Principles and Techniques

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Concepts Used:

Organic Chemistry – Some Basic Principles and Techniques - Reaction Mechanism

SN1 Reaction Mechanism:

SN1 reaction mechanism takes place by following three steps –

  • Formation of carbocation 
  • Attack of nucleophile 
  • Deprotonation 

SN2 Reaction Mechanism:

The SN2 reaction mechanism involves the nucleophilic substitution reaction of the leaving group (which generally consists of halide groups or other electron-withdrawing groups) with a nucleophile in a given organic compound.

Electrophilic Aromatic Substitution Reaction Mechanism:

The mechanism of an electrophilic aromatic substitution reaction contains three main components which are:

  1. A new sigma bond from C=C is formed during the reaction in the arene nucleophile.
  2. Due to the breaking of the C-H sigma bond, a proton is removed.
  3. The C=C bond is reformed and it restores the aromaticity of the compound.

Electrophilic Substitution Reaction Mechanism:

The electrophilic substitution reaction mechanism is composed of three steps, which will be discussed more below.

  • Electrophile Generation
  • Carbocation Formation
  • Proton Removal