In the electrolysis of aqueous NaCl (brine), water and NaCl both participate in the redox process.
At the cathode:
Reduction occurs.
Among Na⁺ and H₂O, H₂O gets reduced more easily:
\(2H₂O + 2e⁻ → H₂ + 2OH⁻\)
So, \(H₂\) gas is evolved at the cathode.
At the anode:
Oxidation occurs.
Between Cl⁻ and OH⁻, Cl⁻ gets oxidized more readily:
\(2Cl⁻ → Cl₂ + 2e⁻\)
So, Cl₂ gas is released at the anode.
The correct answer is option (A): H2 at cathode
Conductivity of CH\(_3\)COOH decreases on dilution.
(a) State the following:
(i) Kohlrausch law of independent migration of ions