Question:
Conductivity of CH\(_3\)COOH decreases on dilution.
Conductivity of CH\(_3\)COOH decreases on dilution.
Show Hint
Weak electrolytes like acetic acid dissociate partially, and dilution reduces the number of ions in solution, causing a decrease in conductivity.
Updated On: Feb 28, 2025
Hide Solution
Verified By Collegedunia
Solution and Explanation
The conductivity of acetic acid (CH\(_3\)COOH) decreases on dilution because it is a weak electrolyte that ionizes only partially in solution. As the solution is diluted, the number of ions in the solution decreases, reducing the overall conductivity. In the case of weak electrolytes like acetic acid, dilution reduces the concentration of dissociated ions, leading to a decrease in electrical conductivity.
Was this answer helpful?
0
0
Top Questions on Electrolytic Cells and Electrolysis
(a) State the following:
(i) Kohlrausch law of independent migration of ions
- CBSE CLASS XII - 2025
- Chemistry
- Electrolytic Cells and Electrolysis
- Faraday’s First Law of Electrolysis
Faraday's first law of electrolysis states that the mass of a substance deposited or liberated at an electrode during electrolysis is directly proportional to the quantity of electricity (charge) passed through the electrolyte.
Mathematically, it is expressed as: \[ m = ZQ \] where:- \( m \) is the mass of the substance deposited (in grams),
- \( Z \) is the electrochemical equivalent of the substance,
- \( Q \) is the total charge passed through the electrolyte (in coulombs).
- CBSE CLASS XII - 2025
- Chemistry
- Electrolytic Cells and Electrolysis
- On the basis of \( E^\circ \) values, O\(_2\) gas should be liberated at the anode, but it is Cl\(_2\) gas that is liberated in the electrolysis of aqueous NaCl.
- CBSE CLASS XII - 2025
- Chemistry
- Electrolytic Cells and Electrolysis
- The reactions taking place during electrolysis of aqueous solution of CuCl2 with platinum electrodes are :
A. Cu2+(aq) + 2e- → Cu(s)
B. H+(aq) + e- → \(\frac{1}{2}H_2(g)\)
C. H2O(l) + e- → \(\frac{1}{2}H_2(g)+^-OH(aq)\)
D. Cl-(aq) → \(\frac{1}{2}Cl_2(g)+e^-\)
E. 2-OH(aq) → H2O(l) + \(\frac{1}{2}O_2(g)+2e^-\)
Choose the correct answer from the options given below :- CUET (UG) - 2023
- Chemistry
- Electrolytic Cells and Electrolysis
- If we use molten NaCl, the products of electrolysis are ____.
- CUET (UG) - 2023
- Chemistry
- Electrolytic Cells and Electrolysis
View More Questions
Questions Asked in CBSE CLASS XII exam
The correct IUPAC name of \([ \text{Pt}(\text{NH}_3)_2\text{Cl}_2 ]^{2+} \) is:
- CBSE CLASS XII - 2025
- Coordination Compounds
- A 1 cm segment of a wire lying along the x-axis carries a current of 0.5 A along the \( +x \)-direction. A magnetic field \( \mathbf{B} = (0.4 \, \text{mT}) \hat{j + (0.6 \, \text{mT}) \hat{k} \) is switched on in the region. The force acting on the segment is:}
- CBSE CLASS XII - 2025
- Magnetic Effects of Current and Magnetism
- Using integration, find the area of the region bounded by the line \[ y = 5x + 2, \] the \( x \)-axis, and the ordinates \( x = -2 \) and \( x = 2 \).
- CBSE CLASS XII - 2025
- Evaluation of Definite Integrals by Substitution
- Two conductors A and B of the same material have their lengths in the ratio 1:2 and radii in the ratio 2:3. If they are connected in parallel across a battery, the ratio \( \frac{v_A}{v_B} \) of the drift velocities of electrons in them will be:
- CBSE CLASS XII - 2025
- Current electricity
- Arun, Bashir and Joseph were partners in a firm sharing profits and losses in the ratio of 5 : 3 : 2. They admitted Daksh as a new partner who acquired his share entirely from Arun. If Arun sacrificed \( \frac{1}{5} \)th from his share to Daksh, Daksh's share in the profits of the firm will be :
- CBSE CLASS XII - 2025
- Partnership Accounts
View More Questions