एका मूलद्रव्याची इलेक्ट्रॉन संरचना 2, 8, 1 अशी आहे. त्यावरून खालील प्रश्नांची उत्तरे लिहा :
(अ) या मूलद्रव्याचा अणुक्रमांक किती ?
(ब) या मूलद्रव्याचा गण कोणता ?
(क) हे मूलद्रव्य कोणत्या आवर्तात आहे ?
एका मूलद्रव्याची इलेक्ट्रॉन संरचना 2, 8, 1 अशी आहे. त्यावरून खालील प्रश्नांची उत्तरे लिहा :
(अ) या मूलद्रव्याचा अणुक्रमांक किती ?
(ब) या मूलद्रव्याचा गण कोणता ?
(क) हे मूलद्रव्य कोणत्या आवर्तात आहे ?
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Solution and Explanation
Step 1: दिलेली इलेक्ट्रॉन संरचना.
मूलद्रव्याची इलेक्ट्रॉन संरचना 2, 8, 1 अशी आहे.
याचा अर्थ पहिल्या कक्षेत 2, दुसऱ्या कक्षेत 8 आणि तिसऱ्या कक्षेत 1 इलेक्ट्रॉन आहेत.
Step 2: अणुक्रमांक काढा.
अणुक्रमांक म्हणजे एकूण इलेक्ट्रॉन्सची संख्या.
\[
2 + 8 + 1 = 11
\]
म्हणून अणुक्रमांक = 11.
Step 3: गण ठरवा.
बाह्य कक्षेतील (Valence Shell) इलेक्ट्रॉन्सची संख्या = 1.
म्हणून हे मूलद्रव्य पहिल्या (I) गणात येते.
Step 4: आवर्त ठरवा.
कक्षांची एकूण संख्या = 3 असल्याने हे मूलद्रव्य तिसऱ्या (III) आवर्तात आहे.
Step 5: निष्कर्ष.
अणुक्रमांक = 11, गण = पहिला (I), आवर्त = तिसरे (III).
म्हणून हे मूलद्रव्य सोडियम (Na) आहे.
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