During the electrolysis of water, the following reactions occur:
The reduction half-reaction at the cathode is:
\(2H_2O \rightarrow [2e^-] H_2 + 2OH^-\)
The oxidation half-reaction at the anode is:
\(2Cl^- \rightarrow [2e^-] Cl_2 + 2e^-\)
The formula for calculating the time required for electrolysis is given by:
\(\frac{W}{E} = \frac{It}{96500}\)
Where: - \( W \) is the weight of the substance being electrolyzed, - \( E \) is the equivalent weight of the substance, - \( I \) is the current, - \( t \) is the time in seconds, - 96500 is the Faraday constant (in coulombs per mole).
Substitute the given values into the equation:
\(0.1 \times 2 = \frac{3 \times t}{96500}\)
Simplifying for \( t \), we get:
\(t = 6433 \, \text{seconds}\)
Converting seconds to minutes:
\(t = 107.2 \, \text{minutes} \approx 110 \, \text{minutes}\)
The time required for electrolysis is approximately \( 110 \, \text{minutes} \).
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :
An electrochemical cell is a device that is used to create electrical energy through the chemical reactions which are involved in it. The electrical energy supplied to electrochemical cells is used to smooth the chemical reactions. In the electrochemical cell, the involved devices have the ability to convert the chemical energy to electrical energy or vice-versa.