Question:

During electrolysis of an aqueous solution of NaCl:

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In aqueous electrolysis, hydrogen is reduced at the cathode, and halide ions (Cl\(^-\)) are oxidized at the anode instead of water.
Updated On: Feb 25, 2025
  • \( H_2(g) \) is liberated at cathode
  • \( Na \) is formed at cathode
  • \( O_2(g) \) is liberated at anode
  • \( Cl_2(g) \) is liberated at cathode
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The Correct Option is A

Solution and Explanation

During the electrolysis of aqueous NaCl, the following reactions occur: At the Cathode (\(-\)): Reduction occurs: \[ 2H_2O + 2e^- \rightarrow H_2 (g) + 2OH^- \] Since the reduction potential of H\(^+\) (-0.83 V) is more positive than Na\(^+\) (-2.71 V), H\(_2\) gas is liberated instead of Na deposition. At the Anode (\(+\)): Oxidation occurs: \[ 2Cl^- \rightarrow Cl_2 (g) + 2e^- \] Since the oxidation potential of Cl\(^-\) is higher than that of water, Cl\(_2\) gas is released at the anode. Thus, H\(_2\) gas is liberated at the cathode.
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