Question:

During a half-moon phase, the Earth-Moon-Sun form a right triangle. If the Moon-Earth-Sun angle at this half-moon phase is measured to be \( 89.85^\circ \), the ratio of the Earth-Sun and Earth-Moon distances is closest to:

Show Hint

For problems involving right triangles and trigonometric ratios, ensure accurate angle measurements and use precise trigonometric values for calculations.
Updated On: Jan 24, 2025
  • 328
  • 382
  • 238
  • 283
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Step 1: Use the trigonometric relationship.
During the half-moon phase, the Earth-Moon-Sun form a right triangle. Using the tangent of the Moon-Earth-Sun angle \( 89.85^\circ \): \[ tan} \, \theta = \frac{Earth-Moon distance}}{Earth-Sun distance}}. \]
Rewriting: \[ Earth-Sun distance} = \frac{Earth-Moon distance}}{tan} \, \theta}. \]
Step 2: Substitute the values.
With \( \theta = 89.85^\circ \), \( tan} \, \theta \approx 0.002618 \). Hence:
\[ \frac{Earth-Sun distance}}{Earth-Moon distance}} = \frac{1}{0.002618} \approx 382. \]
Step 3: Conclusion.
The ratio of Earth-Sun to Earth-Moon distances is closest to \( 382 \).
Was this answer helpful?
0
0