Step 1: Let the original price of the ticket be P. The first discount of x% reduces the price to:
\[ P \times \left(1 - \frac{x}{100} \right). \]
The second discount of x% is applied to the new price:
\[ P \times \left(1 - \frac{x}{100} \right) \times \left(1 - \frac{x}{100} \right). \]
The total price after both discounts is:
\[ P \times \left(1 - \frac{x}{100} \right)^2. \]
Step 2: The total discount is 36%, so the final price is 64% of the original price:
\[ P \times \left(1 - \frac{x}{100} \right)^2 = P \times 0.64. \]
Step 3: Dividing both sides by P:
\[ \left(1 - \frac{x}{100} \right)^2 = 0.64. \]
Taking the square root of both sides:
\[ 1 - \frac{x}{100} = 0.8 \Rightarrow \frac{x}{100} = 0.2 \Rightarrow x = 20. \]
Conclusion: The value of x is 20%.
List-I | List-II |
---|---|
(A) Confidence level | (I) Percentage of all possible samples that can be expected to include the true population parameter |
(B) Significance level | (III) The probability of making a wrong decision when the null hypothesis is true |
(C) Confidence interval | (II) Range that could be expected to contain the population parameter of interest |
(D) Standard error | (IV) The standard deviation of the sampling distribution of a statistic |