Dry air is passed through a solution containing $ 10\,g $ of a solute in $ 90\,g $ of water and then through pure water. The loss in weight of solution is $ 2.5\,g $ and that of pure solvent is $ 0.05 \,g $ . Calculate the molecular weight of the solute.
- 50
- 180
- 102
- 25
The Correct Option is C
Solution and Explanation
$ =\frac{0.05}{2.55}=\frac{1}{51} $
Weight of solute $ =\frac{w}{W}\times M\times \frac{p}{p-{{p}_{s}}} $
$ =\frac{10\times 18}{90}\times 51 $
$ =102g $
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Concepts Used:
Solutions
A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.
For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.
Types of Solutions:
The solutions can be classified into three types:
- Solid Solutions - In these solutions, the solvent is in a Solid-state.
- Liquid Solutions- In these solutions, the solvent is in a Liquid state.
- Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.
On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:
- Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
- Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
- Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.