Step 1: Wheatstone’s bridge principle.
It is based on the principle of null deflection, where no current flows through the galvanometer if the bridge is balanced.
Step 2: Circuit diagram.
The bridge has four resistors $P$, $Q$, $R$, and $S$ connected in a quadrilateral. A galvanometer is connected between two opposite corners, and a battery between the remaining two corners.
\[
\text{Balanced condition: } \frac{P}{Q} = \frac{R}{S}
\]
Step 3: Conjugate arms.
Conjugate arms are opposite pairs: (P, Q) with (R, S). Specifically, AB and CD are conjugate arms; AD and BC are also conjugate arms.
Step 4: Conclusion.
Wheatstone’s bridge works on balancing ratios of conjugate arms.