Question:

Double integral 0202xx2xdydxx2+y2\int\limits_0^2\int\limits_0^{\sqrt{2x-x^2}}\frac{xdydx}{\sqrt{x^2+y^2}} equals:

Updated On: Mar 21, 2024
  • 23\frac{2}{3}
  • 43\frac{4}{3}
  • 13\frac{1}{3}
  • 83\frac{8}{3}
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The Correct Option is B

Solution and Explanation

The correct option is(B)
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