What is the output of the following C code?
void foo(int *p, int x) {
*p = x;
}
void main() {
int *z;
int a = 20, b = 25;
z = a; // Incorrect: Should be z = a;
foo(z, b);
printf("%d", a);
}
Issue: The statement z = a; is invalid because a is an integer, and z is a pointer.
What is the output of the following C code?
void foo(int *p, int x) {
*p = x;
}
void main() {
int *z;
int a = 20, b = 25;
z = a; // Incorrect: Should be z = a;
foo(z, b);
printf("%d", a);
}
Issue: The statement z = a; is invalid because a is an integer, and z is a pointer.
Show Hint
20
25
30
Undefined
The Correct Option is B
Solution and Explanation
Step 1: Understanding the Code
- Initially,
ais set to 20, andbis set to 25.zis a pointer toa. - The function
foo(z, b)modifies the value ofathrough the pointerz, assigningathe value ofb(25).
Step 2: Conclusion
- After the function call, the value of
abecomes 25, which is printed.
Thus, the correct answer is (B).
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