Question:

\(\displaystyle \int \frac{3x^{2}+2}{x^{3}+2x}\,dx=\ \ ?\)

Show Hint

Try to see the denominator's derivative sitting upstairs.
  • \(\sin^{-1}(x^{3}+3x)+k\)
  • \(\tan^{-1}(3x^{2}+2)+k\)
  • \(\log|3x^{2}+2|+k\)
  • \(\log|x^{3}+2x|+k\)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

Let \(g(x)=x^{3}+2x\Rightarrow g'(x)=3x^{2}+2\) (the numerator). Therefore \(\int\dfrac{g'(x)}{g(x)}dx=\ln|g(x)|+k=\ln|x^{3}+2x|+k\).
Was this answer helpful?
0
0