Question:

Differentiate between elimination and substitution reactions in haloalkanes by an example.

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Elimination forms alkenes, while substitution forms alcohols.
Updated On: Mar 5, 2025
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Solution and Explanation

- Elimination: Haloalkane reacts with \( alc. \, KOH \) to form an alkene. \[ C_2H_5Br + alc.\,KOH \rightarrow C_2H_4 + HBr. \] - Substitution: Haloalkane reacts with \( aq. \, KOH \) to form an alcohol. \[ C_2H_5Br + aq.\,KOH \rightarrow C_2H_5OH + KBr. \]
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