Step 1: Volume of the cube Let the side of the cube be $a$. The volume of the cube is: \[ V_{\text{cube}} = a^3. \] Step 2: Volume of the sphere The sphere that fits exactly inside the cube will have a diameter equal to the side of the cube, $a$. The radius of the sphere is: \[ r = \frac{a}{2}. \] The volume of the sphere is: \[ V_{\text{sphere}} = \frac{4}{3} \pi r^3 = \frac{4}{3} \pi \left(\frac{a}{2}\right)^3. \] Simplify: \[ V_{\text{sphere}} = \frac{4}{3} \pi \cdot \frac{a^3}{8} = \frac{\pi a^3}{6}. \] Step 3: Find the ratio The ratio of the volume of the cube to the volume of the sphere is: \[ \text{Ratio} = \frac{V_{\text{cube}}}{V_{\text{sphere}}} = \frac{a^3}{\frac{\pi a^3}{6}} = \frac{6}{\pi}. \] Correct Answer: The ratio is $6 : \pi$.
| Class | 0 – 15 | 15 – 30 | 30 – 45 | 45 – 60 | 60 – 75 | 75 – 90 |
|---|---|---|---|---|---|---|
| Frequency | 11 | 8 | 15 | 7 | 10 | 9 |
Leaves of the sensitive plant move very quickly in response to ‘touch’. How is this stimulus of touch communicated and explain how the movement takes place?