To determine the order and degree of the given differential equation, follow these steps:
Step 1: {Order of the differential equation} The order of a differential equation is the highest derivative that appears in the equation. In this case, the highest derivative is \( \frac{d^3y}{dx^3} \), which indicates that the order of the differential equation is 3.
Step 2: {Degree of the differential equation} The degree of the differential equation is the power of the highest derivative after clearing any radicals and fractional powers. In the given equation, the highest derivative is \( \frac{d^3y}{dx^3} \), which appears with a fractional power of \( \left[1 + \left(\frac{dy}{dx}\right)^2\right]^{5/2} \). To clear the fractional exponent, raise both sides of the equation to the power of \( \frac{2}{5} \), which will remove the fractional power and give a polynomial form. The degree of the differential equation is the exponent of the highest derivative after this operation. The degree becomes 5, as the exponent \( \frac{5}{2} \) is cleared to become 5. Thus, the order is 3, and the degree is 5.
If the roots of $\sqrt{\frac{1 - y}{y}} + \sqrt{\frac{y}{1 - y}} = \frac{5}{2}$ are $\alpha$ and $\beta$ ($\beta > \alpha$) and the equation $(\alpha + \beta)x^4 - 25\alpha \beta x^2 + (\gamma + \beta - \alpha) = 0$ has real roots, then a possible value of $y$ is:
Which of the following are ambident nucleophiles?
[A.] CN$^{\,-}$
[B.] CH$_{3}$COO$^{\,-}$
[C.] NO$_{2}^{\,-}$
[D.] CH$_{3}$O$^{\,-}$
[E.] NH$_{3}$
Identify the anomers from the following.

The standard Gibbs free energy change \( \Delta G^\circ \) of a cell reaction is \(-301 { kJ/mol}\). What is \( E^\circ \) in volts?
(Given: \( F = 96500 { C/mol}\), \( n = 2 \))