Question:

Describe the change in hybridisation (if any) of the Al atom in the following reaction.
\(AlCl_3+Cl^- \rightarrow AlCl_4^-\)

Updated On: Dec 13, 2024
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Solution and Explanation

The valence orbital picture of aluminium in the ground state can be represented as:
The valence orbital picture of aluminium in the ground state
The orbital picture of aluminium in the excited state can be represented as:
The orbital picture of aluminium in the excited state

Hence, it undergoes \(sp ^2\) hybridization to give a trigonal planar arrangement (in \(AlCl_3\)). 
To form \(AlCl_4^ -\) , the empty \(3p_z\) orbital also gets involved and the hybridization changes from \(sp ^2\) to \(sp ^3\) . 
As a result, the shape gets changed to tetrahedral.

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Concepts Used:

Chemical Bonding and Molecular Structure

Such a group of atoms is called a molecule. Obviously, there must be some force that holds these constituent atoms together in the molecules. The attractive force which holds various constituents (atoms, ions, etc.) together in different chemical species is called a chemical bond.

Types of Chemical Bonds:

There are 4 types of chemical bonds which are formed by atoms or molecules to yield compounds. 

  • Ionic Bonds - Ionic bonding is a type of chemical bonding which involves a transfer of electrons from one atom or molecule to another.
  • Covalent Bonds - Compounds that contain carbon commonly exhibit this type of chemical bonding. 
  • Hydrogen Bonds -  It is a type of polar covalent bonding between oxygen and hydrogen wherein the hydrogen develops a partial positive charge
  • Polar Bonds - In Polar Covalent chemical bonding, electrons are shared unequally since the more electronegative atom pulls the electron pair closer to itself and away from the less electronegative atom.

Factors Affecting Bond Enthalpy in Chemical Bonding:

  • Size of the Atom
  • Multiplicity of Bonds
  • Number of Lone Pair of Electrons Present
  • Bond Angle