Question:

$CuSO_4 $ when reacts with KCN forms CuCN which is insoluble in water. It is soluble in excess of KCN due to the formation of the complex :-

Updated On: Apr 29, 2024
  • $K_2[Cu(CN)_4] $
  • $K_3[Cu(CN)_4] $
  • $Cu(CN)_2 $
  • $Cu[KCu(CN)_4] $
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The Correct Option is B

Solution and Explanation

$CuSO_4 $ reacts with KCN to give a white precipitate of cuprous cyanide and cyanogen gas.
The cuprous cyanide dissolves in excess of KCN forming $K_3[Cu(CN)_4] $
$CuSO_4+2KCN \rightarrow K_2SO_4+Cu(CN)_2 $
$\hspace57mm Unstable $
$2Cu(CN)_2 \rightarrow 2CuCN+CN-CN$
$\hspace30mm Insoluble\, \, cyanogen $
$CuCN+3KCN \rightarrow K_3[Cu(CN)_4]$
$\hspace45mm Soluble $
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Concepts Used:

Coordination Compounds

A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.

Coordination entity:

A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.

Ligands:

A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.