Question:

Cuprous ion $(Cu^+ )$ is colourless whereas cupric ion $(Cu^{++} )$ is blue in the aqueous solution. Cuprous ion $(Cu^+ )$ has unpaired electrons while cupric ion $(Cu^{++} )$ does not.

Updated On: Jul 28, 2022
  • If both assertion and reason are true and reason is a correct explanation of the assertion
  • If both the assertion and reason are true but the reason is not a correct explanation of the assertion
  • If the assertion is true but the reason is false
  • If both the assertion and reason are false
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The Correct Option is C

Solution and Explanation

Cuprous ions $\left( Cu ^{+}\right)$ is colourless because it has no unpaired electrons in the $3d$ sub-shell as it has $3 d ^{10}$ configuration. The cupric ion $\left( Cu ^{++}\right)$ has one unpaired electron as it has configuration $3 d^{9}$. By absorbing the visible light, the unpaired electron can migrate from one set of $d$- orbitals to another under the applied field of water molecules. Hence, cupric ion $\left( Cu ^{++}\right)$ in aqueous solution shows blue colour.
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Concepts Used:

D and F Block Elements

The d-block elements are placed in groups 3-12 and F-block elements with 4f and 5f orbital filled progressively. The general electronic configuration of d block elements and f- block elements are (n-1) d 1-10 ns 1-2 and (n-2) f 1-14 (n-1) d1 ns2 respectively. They are commonly known as transition elements because they exhibit multiple oxidation states because of the d-d transition which is possible by the availability of vacant d orbitals in these elements. 

They have variable Oxidation States as well as are good catalysts because they provide a large surface area for the absorption of reaction. They show variable oxidation states to form intermediate with reactants easily. They are mostly lanthanoids and show lanthanoid contraction. Since differentiating electrons enter in an anti-penultimate f subshell. Therefore, these elements are also called inner transition elements.

Read More: The d and f block elements