Question:
$CsBr$ has $bcc$ structure with edge length $4.3\,?$ The shortest inter ionic distance in between $Cs^+$ and $Br^-$ is
$CsBr$ has $bcc$ structure with edge length $4.3\,?$ The shortest inter ionic distance in between $Cs^+$ and $Br^-$ is
Updated On: Jul 6, 2022
- 3.72
- 1.86
- 7.44
- 4.3
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The Correct Option is A
Solution and Explanation
For bcc structure, atomic radius, $r = \frac{\sqrt{3}}{4} a $
$ = \frac{\sqrt{3}}{4} \times 4.3 = 1.86$
Since, r = half the distance between two nearest neighbouring atoms.
$\therefore$ Shortest inter ionic distance = 2 $\times $ 1.86
= 3.72
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Concepts Used:
Solid State
Solids are substances that are featured by a definite shape, volume, and high density. In the solid-state, the composed particles are arranged in several manners. Solid-state, in simple terms, means "no moving parts." Thus solid-state electronic devices are the ones inclusive of solid components that don’t change their position. Solid is a state of matter where the composed particles are arranged close to each other. The composed particles can be either atoms, molecules, or ions.
Types of Solids:
Based on the nature of the order that is present in the arrangement of their constituent particles solids can be divided into two types;
- Amorphous solids behave the same as super cool liquids due to the arrangement of constituent particles in short-range order. They are isotropic and have a broad melting point (range is about greater than 5°C).
- Crystalline solids have a fixed shape and the constituent particles are arranged in a long-range order.