Crystal field stabilisation energy for high spin $d^4$ octahedral complex is
- $-1.8\Delta_0$
- $-1.6\Delta_0+P$
- $-1.2\Delta_0$
- $-0.6\Delta_0$
The Correct Option is D
Solution and Explanation
For high spin $d^4$ octahedral complex Crystal field stabilisation energy
$= (- 3 \times 0.4 + 1 \times 0.6) \Delta_0$
$= (-1.2+ 0.6) \Delta_0 = - 0.6 \Delta_0$
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Concepts Used:
Coordination Compounds
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
Coordination entity:
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
Ligands:
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.