Step 1: Understanding the process of water absorption.
Water absorption by root hairs occurs in three distinct stages:
Imbibition: This is the initial stage where water is absorbed by hydrophilic substances (e.g., cell wall components like cellulose) through capillary action.
Diffusion: After imbibition, water molecules diffuse from regions of higher concentration (soil solution) to lower concentration (root hair cells).
Osmosis: Finally, water moves through the semipermeable membranes of root hair cells into the root cortex via osmotic gradients.
Step 2: Explanation of the correct sequence.
The correct sequence in water absorption is: \[ \text{Imbibition} \rightarrow \text{Diffusion} \rightarrow \text{Osmosis}. \] Imbibition occurs first as the cell walls absorb water. Diffusion facilitates water movement to the root hair cytoplasm. Osmosis enables water transport across membranes into deeper root cells.
Step 3: Explanation of other options.
Option (B): Incorrect. Osmosis does not occur first; imbibition precedes it.
Option (C): Incorrect. Diffusion does not occur before imbibition.
Option (D): Incorrect. Osmosis occurs after diffusion, not before. \[ \therefore \text{The correct sequence is: Imbibition, diffusion, osmosis.} \]
Identify and define ‘A’ and ‘B’ in relation to the uptake of water by the root:
A current-carrying rectangular loop PQRS is made of uniform wire. The length PR = QS = \( 5 \, \text{cm} \) and PQ = RS = \( 100 \, \text{cm} \). If the ammeter current reading changes from \( I \) to \( 2I \), the ratio of magnetic forces per unit length on the wire PQ due to wire RS in the two cases respectively \( F^{I}_{PQ} : F^{2I}_{PQ} \) is:
A real gas within a closed chamber at \( 27^\circ \text{C} \) undergoes the cyclic process as shown in the figure. The gas obeys the equation \( PV^3 = RT \) for the path A to B. The net work done in the complete cycle is (assuming \( R = 8 \, \text{J/molK} \)):
Figure shows a part of an electric circuit. The potentials at points \( a, b, \text{and} \, c \) are \( 30 \, \text{V}, 12 \, \text{V}, \, \text{and} \, 2 \, \text{V} \), respectively. The current through the \( 20 \, \Omega \) resistor will be: